(3x^2+7x-20)/(x+4)

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Solution for (3x^2+7x-20)/(x+4) equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

(3*x^2+7*x-20)/(x+4) = 0

3*x^2+7*x-20 = 0

3*x^2+7*x-20 = 0

DELTA = 7^2-(-20*3*4)

DELTA = 289

DELTA > 0

x = (289^(1/2)-7)/(2*3) or x = (-289^(1/2)-7)/(2*3)

x = 5/3 or x = -4

(x+4)*(x-5/3) = 0

x-5/3 = 0

x-5/3 = 0 // + 5/3

x = 5/3

x = 5/3

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